18x^2+75x=0

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Solution for 18x^2+75x=0 equation:



18x^2+75x=0
a = 18; b = 75; c = 0;
Δ = b2-4ac
Δ = 752-4·18·0
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-75}{2*18}=\frac{-150}{36} =-4+1/6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+75}{2*18}=\frac{0}{36} =0 $

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